Write the equation of a line that is perpendicular to y=-2/7x + 9 and that passes through the point (-4,6) [FP]​

$y=(7/2)x+20$

Step-by-step explanation:

SInce the gradient of the first line is $-2/7$ then the gradien of the perpendicular line is $7/2$.

Therefore by the point slope formula the line that we are looking for is

$y-6=(7/2)(x+4)$

$y=(7/2)x + 20$

x = -2

y = 848

step-by-step explanation:

plug in the numbers

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2