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Mathematics, 27.08.2021 23:20 Pizzapegasus1

Sea ABCD un cuadrilatero convexo. R y S son puntos sobre DC y AB, respectivamente, tales que AD = RC y BC = SA. Sean P, Q y M los puntos medios de RD, BS y CA, respectivamente. Si ∠MP C + ∠MQA = 90°, demuestre que ABCD es un cuadrilatero cıclico.

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