− 4 − [2+4( − 6) − 4 −(2²-5×21)]

1

Step-by-step explanation:

First, solve four your last bracket, 2 squared is 4 and minus 5 is -1 times 21 is -21. Yet because the outer symbol is a negative, all signs change-making 21 positive. Solve 4*-6, and you get -24. This leaves you with [2-24-4+21] that gives you -5. Yet, because the outer sympol is a negative, 5 becomes positive. This leaves you with 1.

71

Step-by-step explanation:

− 4 − [2 + 4(− 6) − 4 − (2²- 5×21)]

− 4 − [2 + 4(− 6) − 4 − (4 - 5×21)]

− 4 − [2 + (-24) − 4 − (4 - 105)]

− 4 − [-22 − 4 − (-101)]

− 4 − [-22 − 4 + 101]

− 4 − [-22 + 97]

− 4 − [-22 + 97]

− 4 − [75]

− 4 − 75

71

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.