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Mathematics, 25.08.2021 01:30 twinchristiansp4xhd2

Answer the questions 1 to 9. no wrong answersjust right plz help ill give u points 1. (3a²b³)⁴ =
2. (2² m⁵ n³)⁵ =
3. (S÷T)⁷ =
4. (24a⁵b⁸ ÷ 6a³b⁶)² =
5. (8r⁵s⁷t³)⁰ =
6. 4⁻³
7. k⁻⁸ · k⁷ =
8. (10⁻⁴)³ =
9. h⁸ ·h¹¹ · h⁶ =

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Answer the questions 1 to 9. no wrong answersjust right plz help ill give u points 1. (3a²b³)⁴ =
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