John's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs John $5.95 per pound, and type B coffee costs $4.65 per pound. This month's blend used three times as many pounds of type B coffee as type A, for a total cost of $656.70. How many pounds of type A coffee were used?

Let x = the number of lbs of Type A coffee.

We know that this month's blend used 3 times as many pounds of type B coffee as type A coffee.

Total lbs of coffee = x + 3x

The total cost then is:

($ cost for Type A)(x) + ($ cost for Type B)(3x) = $717.60

$5.65x + $4.25(3x) = $717.60

$5.65x + $12.75x = $717.60

$18.40x = $717.60

x = 39 lbs

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: