Is there any value(s) of the domain of x^2+ y^2=8 that passes the vertical line test? If so, name the value(s) and state whether or not the existence of this value makes this relation a function. You can use Desmos to help you explore this idea, if needed.

below

Step-by-step explanation:

First we need to find the domain.

x^2+ y^2 = 8

√x^2 + √y^2 = √8

x + y = ±2√2

So the domain is ±2√2. If you graph the circle you will see that it will in fact fail the vertical line test, mainly because its a circle. If you graph the domain onto the circle, you will see that it will have an affect on it being a relation. A graph will be shown below for a better reference. Keep in mind that ±2.828 is the decimal form of ±2√2.

Best of Luck!

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: