Find the equation of the line that is parallel to y = 4x + 1 and
contains the point (1, 1).
y = [? ]X + [ ]

The equation of a line is:

Since the line has to be parallel to line y = 4x+1. Hence, m = 4.

Given point is (1,1). Let this be the following:

Substitute the point in.

Convert the equation in a slope-intercept form or function form.

First, distribute 4 in the expression.

Add 1 on both sides.

Hence, the line that is parallel to y = 4x+1 and passes through (1,1) is y = 4x-3

answer is 33

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb