Mathematics, 17.08.2021 14:00 TombRaider167

Question 10: If the product of all the numbers from 1 to 100 is divisible by 2^n, then what is the maximum possible value for n: A. 128; B. 87; C. 64; D. 97; E. 70.

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Answer from: KIAZTUNEZ

Step-by-step explanation:

100!=2*3*4*...*100

Counting which numbers are divisible by 2:

2,4,6,8,10,12,14,...,96,98,100 : 50 numbers (100/2=50)

Counting which numbers are divisible by 4=2²:

4,8,12,16,20,...96,100: 25 numbers (100/4=25)

Counting which numbers are divisible by 8=2³:

8,16,24,32,40,...,96: 12 numbers (100/8=12.5 ==> 12)

Counting which numbers are divisible by 16=2⁴:

16,32,48,...,96: 6 numbers (100/16=6.25 ==> 6)

Counting which numbers are divisible by 32=2⁵:

32,64,96 : 3 numbers(100/32=3.125 ==>3)

Counting which numbers are divisible by 64=2⁶:

64 : 1 number (100/64=1.5625 ==>1)

Sum of those numbers= 50+25+12+6+3+1=97

100! is divisible by 2⁹⁷.

Answer D

Answer from: Daruk

There are 50 even numbers - divisible by 2
There are 25 multiples of 4
There are 12 multiples of 8
There are 6 multiples of 16
There are 3 multiples of 32
There is one multiple of 64
Each of these is also counted in the line above

So the unique multiples are (1 x 64) x (2 x 32) x (3 x 16) x (6 x 8) x (13 x 4) x (25 x 2)
= (1 x 2^6) x (2 x 2^5) x (3 x 2^4) x (6 x 2^3) x (13 x 2^2) x (25 x 2^1)
So n = 6 + 10 + 12 + 18 + 26 + 25 = 97

The slow (but easier way) to see this is to write down all the even numbers in factors of 2 and count the number of 2S
Eg 2, 2x2, 2x3, 2x2x2, 2x5, 2x2x3, 2x7, 2x2x2x2, 2x9, 2x2x5, 2x11, 2x2x2x3, 2x13, 2x2x7, 2x15 etc
(This only got to 30 but you should get the idea - there are 26 twos up to there)

This is a tough question to explain simply

Answer from: Quest

the thermometer is precise but not accurate

step-by-step explanation:

Answer from: Quest

$y> \frac{1}{3}x$ and y≤ -x +4 .

step-by-step explanation:

we are given a graph for system of inequalities.

in order to write the system of inequalities for the given graph, we need to find the inequality for each of the line separately.

let us find the slope of dotted line first.

taking two coordinates on the graph.

let us say (0,0) and (3,1).

let us find the slope of the line now.

slope of the dotted line would be = $\frac{1-0}{3-0} = \frac{1}{3}$ .

y-intercept of dotted line is y=0 only.

plugging slope m= $\frac{1}{3}$ and b=0 in slope-intercept form y=mx+b, we get

$y=\frac{1}{3}x$ .

the line is shaded up of that dotted line.

therefore, for shading up we would take greater than inequality symbol > .

and because it's a dotted line we would take only > symbol in place of = sign in above equation of line.

therefore, inequality for dotted line would be

$y> \frac{1}{3}x$ .

let us take two points (3,1) and (0,4) on the solid line.

slope of the solid line would be = $\frac{4-1}{0-3} = \frac{3}{-3}=-1$ .

for the solid line we have y-intercept b= 4.

plugging slope m= -1 and b=4 in slope-intercept form y=mx+b, we get

y = -1x + 4.

the line is shaded down of that solid line.

therefore, for shading down we would take less than inequality symbol < .

and because it's a solid line we would take ≤ symbol in place of = sign in above equation of line.

therefore, inequality for solid line would be

y≤ -x +4 .
Write a system of inequalities to represent the shaded portion of the graph.

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