A scientist removed a sample of 39.1 grams of a chemical from a container. The sample was 5 3/4 grams less than 3/10 of the total mass of the chemical in the container. What was the total mass in grams of the chemical in the container before the scientist removed the sample of 39.1 grams. show work please.

The first thing we must do for this case is to define variables:

x: the total mass of the chemical in the container

y: a sample of a chemical from a container

We have the following equation:

y = (3/10) x - 5 3/4

Then, for y = 39.1 we have:

39.1 = (3/10) x - 5 3/4

Clearing x:

(3/10) x = 39.1 + 5 3/4

(3/10) x = 44.85

x = (10/3) * (44.85)

x = 149.5 grams

the total mass in grams of the chemical in the container before the scientist removed the sample of 39.1 grams was:

x = 149.5 grams.

2

step-by-step explanation:

the answer is y = 11.54

hope this : )