Find the tangent and normal to the curve x^3+xy^2-3x^2+4x+5y+2 at the point (1,-1)

you can't solve x because it is 2 linear equation and you only have one equation

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5

the anwser is x< -17/2

parallel lines have the same slope. so if the green line has a slope of -4, the slope of the red line is also -4.