Raju borrows rupees 16000 for 2years. the rate of interest for two successive years are 10% and 12%. If he repays rupees 5600 at the end of first year, find the amount outstanding at the end of 2 years​

Answer is 12,151 rupees.

16000 rupees : 24(bc 2 years)=666 rupees per month.

666 rupees + 10% of the interest rate for the first year= 732 rupees per month for the first year.

For the first year he had to pay 8792 rupees in total.

For the second year he had to pay 8959 bc the interes rate was 12% for the second year.

He only paid 5600 rupees.

8792 rupees + 8959 rupees = 17,751 rupees.

17,751 rupees - 5600 rupees( that he paid) = 12,151 rupees.

Thank you

What the options to that