35) Like J is represented by the equation 3x-2y=10. Line M is perpendicular to line J at (6,-1) What is the equation of Line M

y=-2/3x+3

Step-by-step explanation:

the equation of line J is y=3/2x-5

perpendicular slope would be -2/3

you want it at point (6, -1) so sub the points into y=-2/3x+b

-1=-2/3(6)+b

-1=-4+b

3=b

y=-2/3x+3

step-by-step explanation:

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