Please solve this radical equation. Show all your steps and explain thoroughly what you did. Thank you for your time and help.

4,3

Step-by-step explanation:

Rearrange the equation :

Then, we must square both sides:

x-3 = x²-6x+9

x²-6x+9-x+3=0

x²-7x+12=0

(x-4)(x-3) =0

So x =4,3

x = 3, x = 4

Step-by-step explanation:

Given

+ 3 = x ( subtract 3 from both sides )

= x - 3 ( square both sides )

x - 3 = (x - 3)²

x - 3 = x² - 6x + 9 ( subtract x - 3 from both sides )

0 = x² - 7x + 12 ← in standard form

0 = (x - 3)(x - 4) ← in factored form

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x - 4 = 0 ⇒ x = 4

As a check

Substitute these values into the equation and if both sides are equal then they are solutions

x = 3 : + 3 = + 3 = 3  = 3 = right side

x = 4 : + 3 = + 3 = 1 + 3 = 4 = right side

solutions are x = 3, x = 4

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: