Please answer both! 36) what is the area of a parallelogram having a base of 2Qft and height as 6/F

37) what is the area of a trapezoid having bases of 2ft and 6ft, and height of 12/jf​

Parallelogram

Solve for area

A=bh

bBase

2

hHeight

Enter value

I don't. Know the second. One

36)12(37)0.67

Step-by-step explanation:

36)A=base×height

A=2×6

A=12

37)A=a+b/2h

A=2+6/12

A=8/12

A=0.67

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

step-by-step explanation: it is d