(sin2x+cos2x)*cosx+2cos2x-sinx=0

Ζ∈)

Step-by-Step Explanation:

(sin2x + cos2x)cos2x + 2cos2x - sinx = 0

⇔cos2x (cosx + 2) + sinx (2cos)2 x – 1) = 0

⇔ cos2x (cosx + 2) + sinx.cos2x = 0

⇔ cos2x (cosx + sinx + 2) = 0

⇔ cos2x  = 0

⇔ 2x = ⇔∈Ζ)

idk

step-by-step explanation:

use that smart brain

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)