Write an equation of the line that is parallel to the given line and passes through the given point. 9. y= -2x+6 (0,-4)

10. -2x+3y=12 (3,2)

pls help me

9.) y=-2x-4

10.)y=2/3x

Step-by-step explanation:

Parallel lines have the same slope, different intercepts

9.) The slope is -2x

To find the parallel line

y-(-4)=-2(x-0)

y+4=-2x

y-4=-2x-4

y=-2x-4

10.) You must first put the equation in slope-intercept form.

-2x+2x+3y=2x+12

3y=2x+12

Divide by 3

3y/3=2x/3+12/3

Simplify

y=2/3x+4

Slope = 2/3x

y-2=2/3(x-3)

y-2=2/3x-6/3

y-2=2/3x-2

y-2+2=2/3x-2+2

y=2/3x

could you reply to this with the question so i can ?