Complete the square to evaluate the definite integral
∫dx/x^2-2x+5

Bounds:1-3

Follow the instruction and complete the square in the denominator:

x ² - 2x + 5 = (x ² - 2x + 1) + 4 = (x - 1)² + 4

Then the integral is

Substitute y = x - 1 and dy = dx :

Substitute y = 2 tan(z) and dy = 2 sec²(z) dz :

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.