Consider a tank in the shape of an inverted circular cone with a height of 20 meters and a top radius of 4 meters. Using 9.8m/s^2 for the acceleration due to gravity and 1,000kg/m^3 as the density of water. Set up the integral that represents the work required to pump the water out of the tank if the tank is full of water but you just want to pump half the water out of the tank (down to a depth of 10 meters) over the top of the tank if: a. the tank is full of water and it is being pumped out of a 1-meter long vertical spout at the top of the tank.
b. the tank is half full of water and it is being pumped out of a 0.5-meter long vertical spout at the top of the tank.
c. the tank is full of water and it is being pumped out over the top of the tank.
d. the tank is full of water but you just want to pump half the water out of the tank out over the top of the tank.

y=mx+b

step-by-step explanation:

m slope, b y-intercept

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.

apex answer is: true.

well

44-3-3-3=35

35+4+4+4+4=51

so the ansewr would be 51 degreesat 7: 00