Mathematics, 06.08.2021 16:40 keke6361
A numerical algorithm is used to solve the following system of equations:
3x1β2x2=1 x1β4x2=β3
The numerical results are x1 = 0.997 and x2 = 1.002. The absolute values of the residuals associated with this numerical solution are (to four decimal places with a leading zero before the decimal point):
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A numerical algorithm is used to solve the following system of equations:
3x1β2x2=1 x1β4x2=β3
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