16-32) What is the equation of the line that is perpendicular to
the given line and passes through the point (3, 0)?
O 3x + 5y = -9
O 3x + 5y = 9
O 5x - 3y = -15
O 5x - 3y = 15

the fourth option : 5x - 3y = 15

Step-by-step explanation:

the slope of the original line is given by the coordinate differences between the 2 points on the line.

remember, the slope is the factor of x in the line equation and is the ratio y/x indicating how many units y is changing, when x changes a certain number of units.

so, to go from (-3. 2) to (2, -1) x changes 5 units and y -3 units.

therefore, the slope is -3/5.

the slope of a perpendicular line simply switched x and y. and the sign of the slope.

therefore the slope of the perpendicular line is 5/3.

and the line equation is

y = (5/3)x + c

to get c we need the point on the line (3, 0).

0 = (5/3)×3 + c = 5 + c

c = -5

y = (5/3)x - 5

3y = 5x - 15

3y - 5x = -15 or (after multiplying both sides by -1)

5x - 3y = 15

answer: 370

step-by-step explanation:

remember use pemdas! there are no parentheses or exponents so lets move onto the first part of the equation: multiplication and division. first, lets break the first part of the equation up into something easier using the distributive property. 28 * 12= (20 *12) + (8*12) you know that 20*12 is 240 and 8*12 is 96. add them and you get 336. then, lets solve the last part of the equation (the last part of pemdas is addition and subtraction). 336 plus 34 is 370. hope this !