A rectangular mural has dimensions of (x + 10) and (x + 3) feet. If the area of the mural is 60 square feet, what are its length and width?

Dimensions are 12 , 5

Step-by-step explanation:

Area of rectangular mural = length * width

length * width = 60 square feet

(x + 10)(x + 3) = 60

Use FOIL method

x*x + x*3 + 10*x + 10*3 = 60

x² + 3x + 10x + 30 = 60      {Combine like terms}

x² + 13x + 30 - 60 = 0

x² + 13x - 30 = 0

Sum = 13

Product = -30

Factors =  15 , -2     (15+ (-2) = 13 ; 15*(-2) = -30)

x² + 15x - 2x - 30 =0  {Rewrite middle terms}

x(x + 15) - 2(x + 15) = 0

(x + 15)(x - 2) =0

x - 2 = 0             {Ignore (x +15) as dimensions wont have a negative value}

x = 2

x + 10 = 2 + 10 = 12

x + 3 = 2 + 3 = 5

Dimensions are 12 , 5

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer