WILL GIVE BRAINLIEST How many integers n between 1 and 100 inclusive are there, such that n^2 + n is divisible by 99

It is 121. For n=1 to 100, there a hundred numbers of the form nn where n and n are juxtaposed. There are 9 two digit numbers 11,22,33.. 99.

Step-by-step explanation:

Any number “nn” is a 2-digit multiple of 11.

To be a square number, a number must have “doubles” of any prime factor. Meaning if it has 11 as a factor, then it must have 11×11, in order to be a square.

The only problem is, “11-squared” does not fall between 1 and 100. It is not a two digit number. It is 121. source quora

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

what is the model?

step-by-step explanation: