1. 1-tan A/1+tan A = Cos A- sinA/ cos A+sin A 2. 1+sin A/cos A = cos A/ 1-sin A

3. ( √ sec2 A - 1) (√1- sin2 A) = sin A

4. √1-sin A/1+ sinA = sec A- tan A​

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb