Normal Distr Use the table below to find the percentage of data items in a normal distribution that lie between z=0.3 and 2 = 2.8.
Iz-score 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0
Percentile 53.98 57.93 61.79 65.54 69.15 72.57 75.80 78.81 81.59 84.13
Z-score 1.1 1.2 1.3 1.4 1.5 1.6 1.7 18 1.9 2.0
Percentile 86.43 88.49 90.32 91.92 93.32 94.52 95.54 96.41 97.13 97.72
z-score 2.1 2.2 2.3 2.4 2.5 2.6 2.7 2.8 2.9
Percentile 98.21 98.61 98.93 99.18 99.38 99.53 99.65 99.74 99.81 99.87
3.0
The percentage of data items in a normal distribution that lie between z=0.3 and z = 2.8 is
96.
>

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant

statement #3: proof- ang is congruent to ang ecd : angles are congruent.  

step-by-step explanation:

1: the missing angles in statement #3  

a.) acb  

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.  

2: the missing word in reason #3  

c.) vertical  

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.  

i hope that was and understanding.

i dont know

step-by-step explanation:

the reason i dont know is because i have not taken this class and for that reason i haven't learned this stuff

hope i could