A spring with constant k = 4 is suspended in a liquid that offers a damping force numerically equal to 8 times the instantaneous velocity. If a mass m is suspended from the spring, determine the values of m for which the subsequent free motion is nonoscillatory. (Assume mass m is greater than zero and enter your answer as a single inequality.)

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.