A bag of marbles contains 11 blue marbles, 4 green marbles, and 5 purple marbles. What is the probability of drawing a green marble, removing it, and then drawing a purple marble?

1/19

Step-by-step explanation:

11 blue marbles, 4 green marbles, and 5 purple marbles = 20 marbles

P( green) = green / total = 4/20 = 1/5

Now keep the green

11 blue marbles, 3 green marbles, and 5 purple marbles = 19 marbles

P(purple) = purple/ total = 5/19

P(green, keep,purple) = 1/5 * 5/19 = 1/19

a: inscribed angles

step-by-step explanation:

i reviewed this question with a peer and teacher, seems to be correct, me later

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb