What are the coordinates of vertices of quadrilateral ABCD? use the coordinates to find the length of DA. Need help ASAP ???

The slope of AB is - 2,

Slope of BC is  

Slope of CD is  

Slope of AD is ,

Step-by-step explanation:

The slope of AB is - 2,

Slope of BC is \frac{1}{2}

2

1

Slope of CD is -\frac{3}{4}−

4

3

Slope of AD is \frac{1}{2}

2

1

,

ABCD is trapezoid because one pair of opposite sides is parallel.

Step-by-step explanation:

Given vertices of quadrilateral ABCD,

A(−1, −1) , B(−3, 3) , C(1, 5) , and D(5, 2),

∵ Slope of a line passes through two points (x_1, y_1)(x

1

,y

1

) and (x_2, y_2)(x

2

,y

2

) is,

m=\frac{y_2-y_1}{xc_2-x_1}m=

xc

2

−x

1

y

2

−y

1

Thus, the slope of AB = \frac{3+1}{-3+1}=\frac{4}{-2}=-2

−3+1

3+1

=

−2

4

=−2

Slope of BC = \frac{5-3}{1+3}=\frac{2}{4}=\frac{1}{2}

1+3

5−3

=

4

2

=

2

1

Slope of CD = \frac{2-5}{5-1}=-\frac{3}{4}

5−1

2−5

=−

4

3

Slope of DA = \frac{-1-2}{-1-5}=\frac{-3}{-6}=\frac{1}{2}

−1−5

−1−2

=

−6

−3

=

2

1

Since, when two line segment having the same slope then they are parallel to each other.

∴ BC ║ DA

A quadrilateral only having two parallel sides is called trapezoid,

Hence, ABCD is a trapezoid.

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hope this .. : d

only 10/60 isn't equivalent

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