9. Raul's teacher purchases two rectangular paintings. The dimensions of the first painting are proportional to the dimensions of the second painting. The dimensions of the first painting are 8 inches by 20 inches. One of the
dimensions of the second painting is 24 inches. Which length, in inches, could be the unknown dimension of the
second painting?

(A) 4
(B)6 2/4
(C)9 3/5
(D)12

(c) 9 3/5

Step-by-step explanation:

This is a ratio question. We can work with the dimensions as fractions and solve through cross-multiplication.

Dimensions of the first painting:

8/20 in.

Possible dimensions of the second painting:

24/x in.

x/24 in.

There are two options, because the given 24 inches may be either a length or width of the painting.

Now, we can use cross-multiplication to try to find x in both scenarios.

Scenario #1

8/20=24/x

8x=480

x=60 in.

60 in. is not an answer. Let's try the other scenario.

Scenario #2

8/20=x/24

192=20x

9.6 in.=x

9.6 can also be written as 9 3/5, which is option C.

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

the number of the people going.

step-by-step explanation:

the cost to buy one movie ticket is $7. if the total cost for the movie is a function of how many people go, then the input is : the number of the people going.