In a large restaurant, an average of 3 out of every 5 customers ask for water with their meal. A random sample of 10 customers is selected. Find the probability that exactly 6 ask for water with their meal. Let X be the random variable that represents the number of these customers who ask for water.

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Step-by-step explanation:

a) Let X be the random variable the number of customers asking for water.

X ~B(10,0.6)

= P(X = 6) =( 0.6)6 ( 0.4)4 10!/6 !*4!

= 0.2508

Y ~B(10,0.4)

= P(Y = 4)=( 0.6)6 ( 0.4)4 10!/6 !*4!

= 0.2508

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

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