Show that the point (−1,−1,1) lies on both planes. Then find a vector parametric equation for the line of intersection.

YES , Point (-1, -1, 1) lies on plane

Step-by-step explanation:

Given:

Equation of plane;

-4x + 2y - z = 1

3x - 2y + 2z = 1

Prove:

Point (-1, -1, 1) lies on plane

Computation:

In equation 1

-4x + 2y - z = 1

By putting values

-4(-1) + 2(-1) - (1) = 1

4 - 2 - 1 = 1

1 = 1

So,

Point (-1, -1, 1) satisfy plane

In equation 2

3x - 2y + 2z = 1

By putting values

3x - 2y + 2z = 1

3(-1) - 2(-1) + 2(1)

-3 + 2 + 2 = 1

1 = 1

So,

Point (-1, -1, 1) satisfy plane

So,

Point (-1, -1, 1) lies on plane

Learn more:

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: