PLEASE HELP!! Find an equation in general form for the straight line that passes through the point (-1.4) and is
perpendicular to the line 2x + 3y = 6

-3x+2y=11

Step-by-step explanation:

first rearrange the given equation to the form y = mx + c

3y = -2x+6

y = -2/3 x + 2

so the gradient is -2/3

the gradient of the perpendicular is -1/(-2/3) = 3/2

so the equation of the new line is y-4 = 3/2(x+1)

2y-8 = 3x+3

-3x+2y=11

pls thank and mark brainliest

Provided by Guathmaths

drop out of school or go to quizlet, quizlet is better

step-by-step explanation:

you can't solve x because it is 2 linear equation and you only have one equation