Find X round to the nearest tenth.

38.3 =x or x=141.8

Step-by-step explanation:

Using the law of sines

sin 27         sin x

=

11                   15

Using cross products

15 sin 27 = 11 sin x

15/11 sin 27 = sin x

Taking the inverse sin of each side

sin^-1 (15/11 sin 27 )= sin ^-1(sin x)

38.24883302 =  x

To the nearest tenth

38.2 =x

or

x=141.8

38.2 degrees

Step-by-step explanation:

Use the law of sines

(sin 27)/11=(sinx)15

15sin(27)=11sin(x)

[15sin(27)]/11=sin(x)

x=arcsin[15sin(27)]/11

rounded to nearest tenth, x=38.2

if im not mistaking its

step-by-step explanation:  

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.