Mathematics, 30.07.2021 14:00 Nobleufia
An object is launched at 14.7 meters per second from an 88.2 meter tall platform. The equation for the object's height
(β)
(
h
)
at time
()
(
t
)
seconds after launch is
β()=β4.92+14.7+88.2
h
(
t
)
=
β
4.9
t
2
+
14.7
t
+
88.2
. Assuming
=0
t
=
0
is when the object is launched and
β=0
h
=
0
is when the object is level with the ground, when does the object strike the ground?
Answers: 3
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