You need a 75% alcohol solution. On hand, you have a 60 mL of a 55% alcohol mixture. You also have 85% alcohol mixture. How much of the 85% mixture will you need to add to obtain the desired solution? You will need mL of the 85% solution

60 mL=55% alcohol

?mL=85% alcohol

85×60÷55

=92.727 mL

I think do like thisI'm not sure

Hope this help you

9514 1404 393

  120 mL

Step-by-step explanation:

Let x represent the amount of 85% solution needed. Then the total amount of alcohol in the mix is ...

  0.55(60) +0.85(x) = 0.75(60 +x)

  33 + 0.85x = 45 +0.75x . . . . . . . eliminate parentheses

  0.85x = 12 +0.75x . . . . . . . . . .subtract 33

  0.10x = 12 . . . . . . . . . . . . . . subtract 0.75x

  x = 120 . . . . . . . . . . . . . . multiply by 10

You will need 120 mL of the 85% solution.

i think the answer is d im not sure

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1