On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles, find the total distance traveled in the two days.

The total distance the driver traveled in the two days is 260 miles

From the question, on the first day, the driver was going as a speed of 40 mph.

Let s be speed

∴

On the second day, he increased the speed to 60 mph

∴

From the statement- If he drove 2 more hours on the first day

Let time be t

Then

hrs

and traveled 20 more miles

Let d be distance  

Then,

miles

From the formula

Distance = Speed × Time

Then,

∴

From above,

miles

hrs

Putting these into

...... (1)

But,

∴

From above,

∴

Put this into equation (1)

Multiply through by 3

∴ miles

∴The distance traveled on the second day is 120 miles

For the distance traveled on the first day,

Substitute into the equation

miles

∴

miles

∴ The distance traveled on the first day is 140 miles

The total distance traveled in the two days =

The total distance traveled in the two days = 120 miles + 140 miles

The total distance traveled in the two days = 260 miles

Hence, the total distance the driver traveled in the two days is 260 miles

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225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225

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step-by-step explanation: