Guided Practice You drop a handball from a height of 100 centimeters. Each curved path has 64% of the height of the previous path.

Write a rule for the sequence using centimeters. The initial height is when n = 1.

What height will the ball reach at the top of the sixth path?

A.
an=100 · (0.64)n−1a subscript n baseline equals 100 times left parenthesis 0.64 right parenthesis superscript n minus 1 baseline; about 10.74 cm

B.
an=0.64 · (100)n−1a subscript n baseline equals 0.64 times left parenthesis 100 right parenthesis superscript n minus 1 baseline; about 0.11 cm

C.
an=1 · (0.64)n−1a subscript n baseline equals 1 times left parenthesis 0.64 right parenthesis superscript n minus 1 baseline; 6,400,000,000 cm

A.

an=100 · (0.64)n−1a subscript n baseline equals 100 times left parenthesis 0.64 right parenthesis superscript n minus 1 baseline; about 10.74 cm

Step-by-step explanation:  I got it off of the internet

Step 1 of 1

In geometric sequence, the ratio between two consecutive terms is constant. This ration is called the common ratio.

Consider the following sequence:

Thus the common ratio of the sequence is .

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You drop a handball from a height of 1 meter. Each curved path has 64% of the height of the previous path.   A. A(n)= 100*(0.64)^n-1

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.