O the area of a rhombus is 24m²
and one of its diagonals 18cm find
the side of the rhombus​

Area of rhombus = 1/2 × d1 × d2

Let the other diagonal be x

ATQ

1/2 × 18 × x = 24

9 × x = 24

x = 24/9

x = 8/3

Now half each diagonal = 9 and 4/3

Now side = b² + p² = h²

9²+(4/3)² = h²

81 + 16/9 = h²

729/9 + 16/9 = h²

745/9 = h²

√(745/9) = h

Therefore the side of the rhombus is √(745/9)cm

Answered by Gauthmath must click thanks and mark brainliest

21

jk it's 20

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