Simplify the following expressions b) y(3y2 - 8xy + 4x) + 3x(2y - 4xy) a) 4x(3x + 7) - 8x(2x - 4) d) y? (4y - 8) - 4y + 6y) c) 6(5x - 12) - 9x(2x2 - 3x + 7) f) y(8x + 3y - 4)-(3x + 7y2) 4x2y(3xy - 7x2 + 8y) - 3xy (12xy-8) 8xy? (7x’y - 3xy) + 3(4x+y) - 7xy?) h) g) 11xyz(3x + 4y - 122) + 3xyz xy(8xy + 12x? - 14y2) – 3x?(7y2 - 11xy) (6xy + 12x*y) - (16y2x + 24x?y2) i) 3x Simplify the following expressions 15x+35xy2-45x”y b) 13xy-262*y+39% 13.xy a) 5.2 -648 +4822-160 802 c) Sz*y+20xy-15 20 d) 1672-8x2 422-1 1) 16x9-3x+24** 5x+3x3 6a6b2+12a2b+-18aºba 2ab(3ab) h) 18x*y2-36x*ya +54x*y* -63.xy 3x4(-3y) g) -81x*y2+21x-15xy+18x3y+9 9xy-12xy i) 24x*y+64xy-36ya 15x2-9x2+2x2 i) Simplify the following expressions (4xy2)2 + v-27x6 b) 9x2y+ + 16x2y+ c) (5x2yz3)3 d) V6426612 + V64a6b12 e) 3x(V9x4) + 3x(1-27x6) If a = -4, b = 1 and c = find the value of each of these expressions​

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

linear pair postulates

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.