Solve the equation for all values of x.
(x2 – 16)(x2 + 49) = 0

-4, 4, 7i, -7i

Step-by-step explanation:

Basically any or each bracket must be equal to 0. If x^2+16 = 0, then x can be 4 and -4, and if x^2+49 is 0, then x =7i or -7i

2

step-by-2step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.