Giải hệ phương trình sau bằng phương pháp khử Gauss 
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x1 − x2 + x3 − 2x4 = 3
2x1 − x2 − x3 + 2x4 = 2
−x1 + 4x2 − 10x3 − x4 = 6

The first digit is in the middle school 100s place

(6,1)(5,4)slope = (4 - 1) / (5 - 6) = 3/-1 = -3y = mx + bslope(m) = -3use either of ur , = 6 and y = 1now sub and find b, the y int1 = -3(6) + b1 = -18 + b1 + 18 = b19 = bso ur equation is : y = -3x + we need it in standard formy = -3x + 3x to both sides3x + y = 19 < == standard form

Is there a picture with the proble