You measure 40 watermelons' weights, and find they have a mean weight of 67 ounces. Assume the population standard deviation is 11.4 ounces. Based on this, what is the maximal margin of error associated with a 99% confidence interval for the true population mean watermelon weight.

Step-by-step explanation:

Sample size

Mean weight

Standard deviation

Confidence Interval

\alpha==0.01

Therefore

From table

Generally, the equation for Margin of error is mathematically given by

Therefore Estimated mean is

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.