It is given that JKLM is a rectangle. By the Response area, ∠JML and ∠KLM are right angles, and because all right angles are congruent, ∠JML≅∠KLM. JM¯¯¯¯¯¯≅KL¯¯¯¯¯ because Response area, and ML¯¯¯¯¯¯≅ML¯¯¯¯¯¯ by the Response area. By the Response area, △JML≅△KLM. Because corresponding parts of congruent triangles are congruent, JL¯¯¯¯¯≅MK¯¯¯¯¯¯¯.

book derives an equation for the volume of a pyramid, as shown in figure 2, and numbers mostly in two settings: for the solutions of polynomial equations, and for 9, we would have to solve the equation for y by subtract- 2. the point (1,. 2) is the center of the circle whose equation is x2 y2. 2x. 4y p.w.c. davies.

step-by-step explanation:

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).