a basketball player makes each free-throw with a probability of 0.3 and is on the line for a one-and-one free throw. (that is, a second throw is allowed only if the first is successful.) what is the probability that the player will score 0 points

0.7 = 70% probability that the player will score 0 points.

Step-by-step explanation:

For each free throw, we have these following probabilities:

0.3 probability the player makes.

0.7 probability the player misses.

What is the probability that the player will score 0 points?

He is only allowed the second if he misses the first, thus, he ends with 0 points only if he misses the first.

For any free throw:

0.7 probability the player misses, so 0.7 = 70% probability that the player misses the first free throw, and 0.7 = 70% probability that the player will score 0 points.

the f

last graph i believe

step-by-step explanation:

worked it out i believe

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: