Complete the square to rewrite y=x^(2)+8x+3 in vertex form, and then identify the minimum y-value of the function

vertex form: y=a(x−h)^2+k, (h,k) is the vertex

y=x^(2)+8x+3

 = (x+4)^2+3-4^2

 = (x+4)^2-13

hence, turning point for this function is (-4,-13)

minimum y-value = -13

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e