Awaterfall has a height of 700 toet. A pebble is thrown upward from the top of the fals with an initial velocity of 20 foot per second. The height of the pebble h in foet anert seconds is given by the equation - - 168° + 204 + 700. How long after the pebble is thrown will it hit the ground?
The time it takes for the pebble to hit the ground is about
(Simplify your answer. Type an integer or decimal rounded to the nearest benth as needed.)

The time it takes for the pebble to hit the ground is about 7.3 seconds.

Step-by-step explanation:

Height after t seconds:

The height of the pebble after t seconds is given by:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots such that , given by the following formulas:

How long after  the pebble is thrown will it hit the ground?

This is t for which

So

Quadratic equation with

Then

The time it takes for the pebble to hit the ground is about 7.3 seconds.

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answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet