Graph the linear equation: y = (2/3) x, by creating a t-chart to plot the points. Show all of your work, attach your t-chart and a labeled graph for full credit.

Step-by-step explanation:

Given linear equation is,

y =

t-chart Or table for the input-output values,

y       -2          0          2            4  

x       -3          0           3            6

Now we have to plot the ordered pairs given in the table,

(-3, -2), (0, 0), (3, 2), (6, 4)

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

what?

step-by-step explanation:

what do you need with. i love quadrants. can you tell me ?