Jim, Katrina, Larry, and Jim have all been invited to a dinner party. They arrive randomly and each person arrives at a different time. a. In how many ways can they​ arrive?
b. In how many ways can Jim arrive first and Kim ​last?
c. Find the probability that Jim will arrive first and Kim last.

a.___ (Type an integer)
b.___ (Type an integer.)
c.___ (Type a fraction. Simplify your answer)

24

6

1/12

Step-by-step explanation:

a) This is a counting problem 4*3*2*1 = 24 different ways.

b) 1 * 2 * 1 * 1   = 2 ways

This is one you should try.

Jim Kat Larry Kim

Jim Larry Kat Kim

You can't get another way.

c)

There are 2 ways that Jim can arrive first and Kim Last shown in b

2/24 = 1/12

i) 4!=24

ii) 2 ways

iii) 2/24=1/12

Answered by gauthmath.

1) c 2143.6 cm

2) c 113.0 m

3) a 33.5 ft

4)   d 2 cm

5) c 20 mm

6) 180 in

7) d 120 ft

m a t h w a y. c o m

step-by-step explanation: