Consider points a, b, and c in the graph. Determine which of these points is relative maxima on the interval x = –1 and x = 2 in the graph.

Given:

The graph of a function is given.

To find:

The point that is the relative maxima on the interval x = –1 and x = 2 in the graph.

Solution:

Relative maxima: It is the maximum point of a function over a short interval.

From the given graph it is clear that the graph of the function over the interval x = –1 and x = 2 has a relative maxima at (0,0).

Clearly, (0,0) is represented by point a.

So, the point a is the relative maxima on the interval x = –1 and x = 2 in the graph.

Therefore, the correct option is A.

d

gimmee one of those gold crowns!

~coco

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240