which of the following is a result of shiftinga circle with equation (×-2)+(y-3)^2= 25 to the left 2 unit ?​

x^2+(y-1)^2=25

Step-by-step explanation:

eqn of circle : (x-h)^2+(y-k)^2=r^2

center of circle = (h,k)

hence, the center of the current circle is (2,3)

moving 2 units to the left would make the center (0,1)

the radius would remain the same (5) , hence the new eqn would be

(x-0)^2+(y-1)^2=25

x^2+(y-1)^2=25

hc ghfrfgb

step-by-step explanation:

gedfgb nbgfrezrdfgbn bgfderdfgbvn bvfdsvcb bvfdfgb gfdgb gfr

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0