The perimeter of an iPad Air is 820 mm. Its length is 100 mm less than twice the width.
If x = the length of the iPad Air and y = the width of the iPad Air, the linear system of
equations that could be used to model this situations is,
2x + 2y = a
bx = cy-d
The value of a is:
A The value of b is:
A The value of c is:
Ą The value of d is:
1

a = 820, b = 1, c = 2, d = 100

Step-by-step explanation:

Let x represent the length of the iPad Air and y represent the width of the iPad Air. Since the perimeter of an iPad Air is 820 mm, hence:

2(length + breadth) = 820

2(x + y) = 820

2x + 2y = 820               (1)

Also, the length is 100 mm less than twice the  width. Therefore:

x = 2y - 100               (2)

Given that the equations be used to model this situations is:

2x + 2y = a

bx = cy-d

Therefore comparing this model with equation 1 and 2, we get that:

a = 820, b = 1, c = 2, d = 100

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.